1) $$arccos(\frac{3}{7}) = a$$
2) $$sin(\frac{\pi}{2} + a) = cos(a)$$
3) $$cos(a) = cos(arccos(\frac{3}{7})) = \frac{3}{7}$$
4) $$5 \cdot \frac{3}{7} = \frac{15}{7}$$
Ответ: $$\frac{15}{7}$$