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МатематикаВопрос:
2.15. sin(2*x + pi/4) = -sqrt(2)/2
Ответ:
This is a sine equation. The angles whose sine is -sqrt(2)/2 are 5*pi/4 and 7*pi/4, plus multiples of 2*pi. We would then solve for x.
Похожие
- 2.13. cos(1/2*x - 2*pi/3) = sqrt(2)/2
- 2.14. cos(2*x + 2*pi/3) = sqrt(2)/2
- 2.16. cos(2*x + 5*pi/6) = sqrt(3)/2
- 2.17. cos(2*x + pi/4) = -sqrt(2)/2
- 2.18. sin(1/2*x - pi/4) = -sqrt(2)/2
- 2.19. cos(2*x - 3*pi/4) = -sqrt(3)/2
- 2.20. sin(3*x - 2*pi/3) = 1/2
- 2.21. cos(1/2*x - 5*pi/6) = sqrt(3)/2
- 2.22. sin(x/3 + pi/6) = sqrt(2)/2
- 2.23. cos(2*x - pi/6) = 1/2
- 2.24. sin(x/3 - pi/4) = -sqrt(3)/2
- 2.25. cos(3*x + 5*pi/6) = 1/2
- 2.26. sin(2*x + 2*pi/3) = sqrt(2)/2
- 2.27. cos(x/3 + 2*pi/3) = -sqrt(2)/2
- 2.28. sin(2*x + 5*pi/6) = sqrt(3)/2
- 2.29. cos(x/3 + pi/6) = -sqrt(3)/2
- 2.30. sin(2*x - 3*pi/4) = -sqrt(3)/2
