Вопрос:

Сократите дробь: (3x^2+2x-1)/(7x-3x^2-2).

Ответ:



\[3x^{2} + 2x - 1 = 0\]


\[x_{1} + x_{2} = - \frac{2}{3}\]


\[x_{1} \cdot x_{2} = - \frac{1}{3}\]


\[\Longrightarrow x_{1} = - 1;\ \ x_{2} = \frac{1}{3}.\]


\[3x^{2} + 2x - 1 =\]


\[= 3 \cdot (x + 1)\left( x - \frac{1}{3} \right) =\]


\[= (x + 1)(3x - 1).\]


\[7x - 3x^{2} - 2 = 0\]


\[3x^{2} - 7x + 2 = 0\]


\[x_{1} + x_{2} = \frac{7}{3}\]


\[x_{1} \cdot x_{2} = \frac{2}{3}\]


\[\Longrightarrow x_{1} = 2;\ x_{2} = \frac{1}{3}.\]


\[7x - 3x^{2} - 2 =\]


\[= - 3 \cdot (x - 2)\left( x - \frac{1}{3} \right) =\]


\[= (2 - x)(3x - 1).\]





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