
a) $$rac{3-\sqrt{3}}{\sqrt{6}-\sqrt{2}} = \frac{\sqrt{3}(\sqrt{3}-1)}{\sqrt{2}(\sqrt{3}-1)}=\frac{\sqrt{3}}{\sqrt{2}} = \frac{\sqrt{3} \cdot \sqrt{2}}{\sqrt{2} \cdot \sqrt{2}} = \frac{\sqrt{6}}{2}$$
Ответ: $$rac{\sqrt{6}}{2}$$
б) $$rac{a-25}{\sqrt{a}-5} = \frac{(\sqrt{a}-5)(\sqrt{a}+5)}{\sqrt{a}-5} = \sqrt{a}+5$$
Ответ: $$\sqrt{a}+5$$