Вопрос:

Solve the system of equations: x/3 - y/2 = -4, x/2 + y/4 = -2

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Ответ:

Multiply the first equation by 6 and the second by 4 to clear denominators: 2x - 3y = -24 and 2x + y = -8.

Subtract the second new equation from the first: (2x - 3y) - (2x + y) = -24 - (-8), which simplifies to -4y = -16, so y = 4.

Substitute y = 4 into the second new equation: 2x + 4 = -8, so 2x = -12, which means x = -6.

Solution: x = -6, y = 4.

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