a) $$3^2 \cdot 2 = 9 \cdot 2 = 18$$
$$(3 \cdot 2)^2 = 6^2 = 36$$
$$18 < 36$$
б) $$2^4 \cdot 2 = 16 \cdot 2 = 32$$
$$2^4 = 16$$
$$32 > 16$$
в) $$(4 \cdot 3)^2 = 12^2 = 144$$
$$4^2 \cdot 3^2 = 16 \cdot 9 = 144$$
$$144 = 144$$
г) $$2^5 \cdot 2 = 32 \cdot 2 = 64$$
$$2^5 \cdot 2^5 = 32 \cdot 32 = 1024$$
$$64 < 1024$$
Ответ: смотри решение