Текстовое задание из поля "Пример" и "Ответ"

Пошаговое решение:

• 1) -3,5 * 3 = -10,5
• 2) -2,7 : (-2) = 1,35
• 3) 7,5 * (-0,4) = -3
• 4) 0,9 : 1,8 = 0,5
• 5) 0,48 : 0,003 = 160
• 6) \( \frac{5}{8} \cdot \frac{5}{24} = \frac{25}{192} \)
• 7) \( \frac{5}{6} : 25 = \frac{5}{6 cdot 25} = \frac{1}{6 cdot 5} = \frac{1}{30} \)
• 8) \( 3 \frac{2}{4} : 1 \frac{3}{8} = \frac{14}{4} : \frac{11}{8} = \frac{14}{4} cdot \frac{8}{11} = \frac{14 cdot 2}{11} = \frac{28}{11} \)
• 9) \( \frac{3}{5} - \frac{5}{7} = \frac{3 cdot 7 - 5 cdot 5}{35} = \frac{21-25}{35} = \frac{-4}{35} \)
• 10) \( 1 \frac{5}{12} \cdot \frac{5}{6} = \frac{17}{12} \cdot \frac{5}{6} = \frac{85}{72} \)
• 11) 2 - 7,98 = -5,98
• 12) -4,73 + 97,3 = 92,57
• 13) -4,73 - 3,3 = -8,03
• 14) 3,989 - (23,989 + 7,4) = 3,989 - 31,389 = -27,4
• 15) 0,2 * 642 * (-0,05) = 128,4 * (-0,05) = -6,42
• 16) \( 1 - \frac{4}{17} = \frac{17-4}{17} = \frac{13}{17} \)
• 17) \( -2 \frac{1}{3} - \frac{1}{4} = -\frac{7}{3} - \frac{1}{4} = \frac{-7 cdot 4 - 1 cdot 3}{12} = \frac{-28-3}{12} = \frac{-31}{12} \)
• 18) \( \frac{1}{8} - \frac{3}{4} = \frac{1 - 3 cdot 2}{8} = \frac{1-6}{8} = \frac{-5}{8} \)
• 19) \( \frac{1}{5} + \frac{6}{12} = \frac{1}{5} + \frac{1}{2} = \frac{1 cdot 2 + 1 cdot 5}{10} = \frac{2+5}{10} = \frac{7}{10} \)
• 20) \( 1 \frac{5}{12} + \frac{5}{6} = \frac{17}{12} + \frac{10}{12} = \frac{27}{12} = \frac{9}{4} \)