Преобразуем выражение:
$$ \frac{n^\frac{5}{6}}{n^{\frac{1}{12}} \cdot n^{\frac{1}{4}}} = \frac{n^{\frac{5}{6}}}{n^{\frac{1}{12} + \frac{1}{4}}} = \frac{n^{\frac{5}{6}}}{n^{\frac{1}{12} + \frac{3}{12}}} = \frac{n^{\frac{5}{6}}}{n^{\frac{4}{12}}} = \frac{n^{\frac{5}{6}}}{n^{\frac{1}{3}}} = n^{\frac{5}{6} - \frac{1}{3}} = n^{\frac{5}{6} - \frac{2}{6}} = n^{\frac{3}{6}} = n^{\frac{1}{2}} = \sqrt{n} $$Подставим значение n = 64:
$$ \sqrt{64} = 8 $$Ответ: 8