Исходное выражение: \[(\sqrt{2}-1)\sqrt{3+2\sqrt{2}} + (1-\sqrt{3})\sqrt{4+2\sqrt{3}}\]
Заметим, что: \[3 + 2\sqrt{2} = 1 + 2\sqrt{2} + 2 = (1 + \sqrt{2})^2\] \[4 + 2\sqrt{3} = 1 + 2\sqrt{3} + 3 = (1 + \sqrt{3})^2\]
Тогда: \[\sqrt{3+2\sqrt{2}} = \sqrt{(1 + \sqrt{2})^2} = 1 + \sqrt{2}\] \[\sqrt{4+2\sqrt{3}} = \sqrt{(1 + \sqrt{3})^2} = 1 + \sqrt{3}\]
\[(\sqrt{2}-1)(1+\sqrt{2}) + (1-\sqrt{3})(1+\sqrt{3})\]
\[(\sqrt{2} + 2 - 1 - \sqrt{2}) + (1 + \sqrt{3} - \sqrt{3} - 3)\] \[= (2 - 1) + (1 - 3)\] \[= 1 - 2\] \[= -1\]
Ответ: -1