Упростите, найдите значение выражения

1. $$\sqrt{64 \cdot 36} = \sqrt{64} \cdot \sqrt{36} = 8 \cdot 6 = 48$$
2. $$\sqrt{0{,}04 \cdot 81} = \sqrt{0{,}04} \cdot \sqrt{81} = 0{,}2 \cdot 9 = 1{,}8$$
3. $$\sqrt{0{,}25 \cdot 0{,}09 \cdot 144} = \sqrt{0{,}25} \cdot \sqrt{0{,}09} \cdot \sqrt{144} = 0{,}5 \cdot 0{,}3 \cdot 12 = 1{,}8$$
4. $$\sqrt{\frac{16}{25} \cdot \frac{49}{64}} = \sqrt{\frac{16}{25}} \cdot \sqrt{\frac{49}{64}} = \frac{4}{5} \cdot \frac{7}{8} = \frac{28}{40} = \frac{7}{10} = 0{,}7$$
5. $$\sqrt{3^8 \cdot 10^4} = \sqrt{(3^4)^2 \cdot (10^2)^2} = 3^4 \cdot 10^2 = 81 \cdot 100 = 8100$$
6. $$\sqrt{18 \cdot 128} = \sqrt{2 \cdot 9 \cdot 2 \cdot 64} = \sqrt{4 \cdot 9 \cdot 64} = \sqrt{4} \cdot \sqrt{9} \cdot \sqrt{64} = 2 \cdot 3 \cdot 8 = 48$$
7. $$\sqrt{162 \cdot 50} = \sqrt{81 \cdot 2 \cdot 25 \cdot 2} = \sqrt{81 \cdot 25 \cdot 4} = \sqrt{81} \cdot \sqrt{25} \cdot \sqrt{4} = 9 \cdot 5 \cdot 2 = 90$$
8. $$\sqrt{2{,}5 \cdot 16{,}9} = \sqrt{\frac{25}{10} \cdot \frac{169}{10}} = \sqrt{\frac{25}{100} \cdot 169} = \sqrt{\frac{25}{100}} \cdot \sqrt{169} = \frac{5}{10} \cdot 13 = \frac{1}{2} \cdot 13 = 6{,}5$$
9. $$\sqrt{22{,}5 \cdot 1{,}6} = \sqrt{\frac{225}{10} \cdot \frac{16}{10}} = \sqrt{\frac{225 \cdot 16}{100}} = \frac{\sqrt{225 \cdot 16}}{\sqrt{100}} = \frac{\sqrt{225} \cdot \sqrt{16}}{10} = \frac{15 \cdot 4}{10} = \frac{60}{10} = 6$$
10. $$\sqrt{1440 \cdot 3{,}6} = \sqrt{144 \cdot 10 \cdot \frac{36}{10}} = \sqrt{144 \cdot 36} = \sqrt{144} \cdot \sqrt{36} = 12 \cdot 6 = 72$$