\(\frac{3x + 9}{x^2 - 2x} : \frac{x + 3}{4x - 8} = \frac{3(x + 3)}{x(x - 2)} : \frac{x + 3}{4(x - 2)} = \frac{3(x + 3)}{x(x - 2)} \cdot \frac{4(x - 2)}{x + 3} = \frac{3 \cdot 4 \cdot (x + 3) \cdot (x - 2)}{x \cdot (x - 2) \cdot (x + 3)} = \frac{12}{x}\)
Ответ: А)