\(1\frac{2}{3}x \cdot (-0,3y) \cdot 5 = \frac{5}{3}x \cdot (-\frac{3}{10}y) \cdot 5 = \frac{5}{3} \cdot (-\frac{3}{10}) \cdot 5 \cdot xy = \frac{5 \cdot (-3) \cdot 5}{3 \cdot 10} xy = \frac{-75}{30} xy = -\frac{5}{2} xy\)
\(-\frac{5}{2} \cdot (-4) \cdot \frac{11}{5} = \frac{5}{2} \cdot 4 \cdot \frac{11}{5} = \frac{5 \cdot 4 \cdot 11}{2 \cdot 5} = \frac{220}{10} = 22\)
Ответ: -\(\frac{5}{2}\)xy; 22.