a) $$ 3\frac{3}{7}x^5y^6 \cdot (-2\frac{1}{3}x^5y) = \frac{24}{7}x^5y^6 \cdot (-\frac{7}{3}x^5y) = -\frac{24 \cdot 7}{7 \cdot 3} x^{5+5} y^{6+1} = -\frac{24}{3} x^{10} y^7 = -8x^{10}y^7 $$
б) $$(a^{n+1})^2 : a^{2n} = a^{2(n+1)} : a^{2n} = a^{2n+2} : a^{2n} = a^{2n+2-2n} = a^2$$
Ответ: а) $$-8x^{10}y^7$$, б) $$a^2$$