а) $$4b^2c : (-2.5bc^4) = \frac{4b^2c}{-2.5bc^4} = -\frac{4}{2.5} \cdot \frac{b^2}{b} \cdot \frac{c}{c^4} = -1.6 \cdot b \cdot \frac{1}{c^3} = -\frac{1.6b}{c^3}$$
б) $$(-2x^{10}y^6)^4 = (-2)^4 \cdot (x^{10})^4 \cdot (y^6)^4 = 16x^{10 \cdot 4}y^{6 \cdot 4} = 16x^{40}y^{24}$$
Ответ: а) $$\frac{-1.6b}{c^3}$$; б) $$16x^{40}y^{24}$$