в)
\(\frac{2}{3}\)a + \(\frac{3}{8}\)b - \(\frac{1}{6}\)a - \(\frac{1}{4}\)b = (\(\frac{2}{3}\) - \(\frac{1}{6}\))a + (\(\frac{3}{8}\) - \(\frac{1}{4}\))b = (\(\frac{4}{6}\) - \(\frac{1}{6}\))a + (\(\frac{3}{8}\) - \(\frac{2}{8}\))b = \(\frac{3}{6}\)a + \(\frac{1}{8}\)b = \(\frac{1}{2}\)a + \(\frac{1}{8}\)b
Ответ: \(\frac{1}{2}\)a + \(\frac{1}{8}\)b