в) (\(\frac{17}{100} + \frac{27}{100}\)) - (\(\frac{8}{100} + \frac{3}{100}\)) = \(\frac{17+27}{100}\) - \(\frac{8+3}{100}\) = \(\frac{44}{100}\) - \(\frac{11}{100}\) = \(\frac{44-11}{100}\) = \(\frac{33}{100}\)
Ответ: \(\frac{33}{100}\)