в) \( \frac{3y}{4y-4} + \frac{2y}{5-5y} \)

Упростим знаменатели: \( 4y-4 = 4(y-1) \), \( 5-5y = -5(y-1) \). Общий знаменатель: \( -20(y-1) \). \[ \frac{3y}{4(y-1)} + \frac{2y}{-5(y-1)} = \frac{15y}{-20(y-1)} + \frac{-8y}{-20(y-1)} = \frac{15y-8y}{-20(y-1)} = \frac{7y}{-20(y-1)} \] Ответ: \( \frac{7y}{-20(y-1)} \).