4) в) \frac{3x-5}{9-x^2} = -10;

4) в) Решим уравнение: $$ \frac{3x-5}{9-x^2} = -10 $$

$$ 3x - 5 = -10(9 - x^2) $$

$$ 3x - 5 = -90 + 10x^2 $$

$$ 10x^2 - 3x - 85 = 0 $$

$$ D = (-3)^2 - 4(10)(-85) = 9 + 3400 = 3409 $$

$$ x_1 = \frac{3 + \sqrt{3409}}{20} $$

$$ x_2 = \frac{3 - \sqrt{3409}}{20} $$

Ответ: $$x_1 = \frac{3 + \sqrt{3409}}{20}, \quad x_2 = \frac{3 - \sqrt{3409}}{20} $$