tg B = \(\frac{AC}{BC}\) = 0.25 = \(\frac{1}{4}\)
BC = 4AC
AB² = AC² + BC²
12² = AC² + (4AC)²
144 = AC² + 16AC²
17AC² = 144
AC² = \(\frac{144}{17}\)
AC = \(\sqrt{\frac{144}{17}}\) = \(\frac{12}{\sqrt{17}}\) = \(\frac{12\sqrt{17}}{17}\)
Ответ: AC = \(\frac{12\sqrt{17}}{17}\)