В. Вычислите: ⁴√0,01 + √0,09; 1/3 · √0,81 + √0,49; 0,25 · √0,25 · √16; 2³ + 5√36; √(2² + 3 · 7); 3√121 − 2√144; √(3² + 4²); 2√(3 · 27) − 6√(2 · 18); √(10² − 4 · 3²); √(4³ + 2³ · 10); √(5² + 2³ · 7); √64 · √100 · √0,16; 2√0,81 + √0,04; 3√25 − 3√81; 1/4 · √(16/25) + 7√0,09; 6√(1 13/36) − 7√(2 2/49); 5√(1 9/16) − 3√(1 17/64); √(16/25) · √(225/64).

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Accepted Answer

\(\sqrt[4]{0.01}+\sqrt{0.09}=\frac{1}{\sqrt{10}}+0.3=\frac{\sqrt{10}+3}{10}\).
\(\frac13\cdot\sqrt{0.81}+\sqrt{0.49}=\frac13\cdot0.9+0.7=1\).
\(0.25\cdot\sqrt{0.25}\cdot\sqrt{16}=0.25\cdot0.5\cdot4=0.5\).
\(2^3+5\sqrt{36}=8+30=38\).
\(\sqrt{2^2+3\cdot7}=\sqrt{25}=5\).
\(3\sqrt{121}-2\sqrt{144}=33-24=9\).
\(\sqrt{3^2+4^2}=\sqrt{25}=5\).
\(2\sqrt{3\cdot27}-6\sqrt{2\cdot18}=2\cdot9-6\cdot6=-18\).
\(\sqrt{10^2-4\cdot3^2}=\sqrt{64}=8\).
\(\sqrt{4^3+2^3\cdot10}=\sqrt{144}=12\).
\(\sqrt{5^2+2^3\cdot7}=\sqrt{81}=9\).
\(\sqrt{64}\cdot\sqrt{100}\cdot\sqrt{0.16}=8\cdot10\cdot0.4=32\).
\(2\sqrt{0.81}+\sqrt{0.04}=2\cdot0.9+0.2=2\).
\(3\sqrt{25}-3\sqrt{81}=15-27=-12\).
\(\frac14\cdot\sqrt{\frac{16}{25}}+7\sqrt{0.09}=\frac14\cdot\frac45+7\cdot0.3=2.3\).
\(6\sqrt{1\frac{13}{36}}-7\sqrt{2\frac2{49}}=6\cdot\frac76-7\cdot\frac{10}{7}=-3\).
\(5\sqrt{1\frac9{16}}-3\sqrt{1\frac{17}{64}}=5\cdot\frac54-3\cdot\frac98=\frac{23}{8}\).
\(\sqrt{\frac{16}{25}}\cdot\sqrt{\frac{225}{64}}=\frac45\cdot\frac{15}{8}=\frac32\).

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