Вариант 12: 1) $\frac{15}{24(\sqrt5)^2}$; 2) $\sqrt{\frac1{121}}+\sqrt{\frac{16}{49}}$; 3) $(\sqrt7-2)(\sqrt7+2)$; 4) $(\sqrt5-\sqrt2)^2$; 5) $0{,}2\sqrt{0{,}25}-\frac16\sqrt{144}$; 6) $10\sqrt5+3\sqrt{125}-4\sqrt{20}$; 7) $\sqrt{\frac{32}{8}}$; 8) $\sqrt{2^6\cdot3^2}$.

Question

Вопрос: $Фото задания: Вариант 12: 1) $\frac{15}{24(\sqrt5)^2}$; 2) $\sqrt{\frac1{121}}+\sqrt{\frac{16}{49}}$; 3) $(\sqrt7-2)(\sqrt7+2)$; 4)…$ Фото задания

Вариант 12: 1) $\frac{15}{24(\sqrt5)^2}$; 2) $\sqrt{\frac1{121}}+\sqrt{\frac{16}{49}}$; 3) $(\sqrt7-2)(\sqrt7+2)$; 4) $(\sqrt5-\sqrt2)^2$; 5) $0{,}2\sqrt{0{,}25}-\frac16\sqrt{144}$; 6) $10\sqrt5+3\sqrt{125}-4\sqrt{20}$; 7) $\sqrt{\frac{32}{8}}$; 8) $\sqrt{2^6\cdot3^2}$.

Accepted Answer

$\frac{15}{24\cdot5}=\frac18$.
$\frac1{11}+\frac47=\frac{51}{77}$.
$7-4=3$.
$5+2-2\sqrt{10}=7-2\sqrt{10}$.
$0{,}2\cdot0{,}5-\frac16\cdot12=0{,}1-2=-1{,}9$.
$10\sqrt5+15\sqrt5-8\sqrt5=17\sqrt5$.
$\sqrt4=2$.
$8\cdot3=24$.

Вариант 12: 1) \(\frac{15}{24(\sqrt5)^2}\); 2) \(\sqrt{\frac1{121}}+\sqrt{\frac{16}{49}}\); 3) \((\sqrt7-2)(\sqrt7+2)\); 4) \((\sqrt5-\sqrt2)^2\); 5) \(0{,}2\sqrt{0{,}25}-\frac16\sqrt{144}\); 6) \(10\sqrt5+3\sqrt{125}-4\sqrt{20}\); 7) \(\sqrt{\frac{32}{8}}\); 8) \(\sqrt{2^6\cdot3^2}\).

Ответ: