Вопрос:

Вариант 2. Определите значение силы тока и напряжения на каждом резисторе, полное сопротивление, полную силу тока и полное напряжение участка. Заполните таблицу.

Смотреть решения всех заданий с листа

Ответ:

R₁ = 20 Ом, R₂ = 30 Ом, R₃ = 50 Ом, R₄ = 15 Ом, R₅ = 10 Ом, I₁ = 5 А.
I_total = I₁ = 5 А.
R_parallel1 = R₁ + R₂ = 20 + 30 = 50 Ом.
R_parallel2 = R₃ = 50 Ом.
R_parallel_combined = 1 / (1/R_parallel1 + 1/R_parallel2) = 1 / (1/50 + 1/50) = 1 / (2/50) = 25 Ом.
R_total = R_parallel_combined + R₄ + R₅ = 25 + 15 + 10 = 50 Ом.
U_total = I_total * R_total = 5 А * 50 Ом = 250 В.
U₁₂ = I_total * R_parallel_combined = 5 А * 25 Ом = 125 В.
U₁ = U₂ = U₁₂ / 2 = 125 В / 2 = 62.5 В. (Assuming R1 and R2 are equal, which they are not. Re-calculating)
U₁₂ = I_total * R_parallel_combined = 5 А * 25 Ом = 125 В.
I₂ = U₁₂ / R₂ = 125 В / 30 Ом = 4.17 А. U₂ = U₁₂ = 125 В.
I₃ = U₁₂ / R₃ = 125 В / 50 Ом = 2.5 А. U₃ = U₁₂ = 125 В.
I₁ = I_total - I₂ - I₃ = 5 - 4.17 - 2.5 = -1.67 А. (This indicates an error in the problem statement or my interpretation of the diagram. Assuming the diagram means R1 and R2 are in series, and R3 is parallel to that combination.)
Let's re-evaluate the parallel branches. Branch 1: R1+R2. Branch 2: R3.
R_branch1 = R₁ + R₂ = 20 + 30 = 50 Ом.
R_branch2 = R₃ = 50 Ом.
R_parallel_branches = 1 / (1/R_branch1 + 1/R_branch2) = 1 / (1/50 + 1/50) = 25 Ом.
R_total = R_parallel_branches + R₄ + R₅ = 25 + 15 + 10 = 50 Ом.
U_total = I_total * R_total = 5 А * 50 Ом = 250 В.
U_parallel_branches = I_total * R_parallel_branches = 5 А * 25 Ом = 125 В.
I_branch1 = U_parallel_branches / R_branch1 = 125 В / 50 Ом = 2.5 А.
I₁ = I_branch1 = 2.5 А. U₁ = I₁ * R₁ = 2.5 А * 20 Ом = 50 В.
I₂ = I_branch1 = 2.5 А. U₂ = I₂ * R₂ = 2.5 А * 30 Ом = 75 В.
I_branch2 = U_parallel_branches / R_branch2 = 125 В / 50 Ом = 2.5 А.
I₃ = I_branch2 = 2.5 А. U₃ = U_parallel_branches = 125 В.
I₄ = I_total = 5 А. U₄ = I₄ * R₄ = 5 А * 15 Ом = 75 В.
I₅ = I_total = 5 А. U₅ = I₅ * R₅ = 5 А * 10 Ом = 50 В.
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