Решение задания 1

a) $$-4^2 \cdot \frac{1}{24} + (\frac{2}{3})^0 = -16 \cdot \frac{1}{24} + 1 = -\frac{16}{24} + 1 = -\frac{2}{3} + 1 = \frac{-2 + 3}{3} = \frac{1}{3}$$.

Ответ: $$ \frac{1}{3} $$

б) $$(-3\frac{1}{3})^2 + (-3)^3 = (-\frac{10}{3})^2 + (-27) = \frac{100}{9} - 27 = \frac{100 - 27 \cdot 9}{9} = \frac{100 - 243}{9} = -\frac{143}{9} = -15\frac{8}{9}$$.

Ответ: $$-15\frac{8}{9}$$