Вариант II

1. Вычислите:

a) $$2\frac{1}{3} \cdot 1\frac{2}{7} = \frac{7}{3} \cdot \frac{9}{7} = \frac{7 \cdot 9}{3 \cdot 7} = \frac{63}{21} = 3$$

г) $$5\frac{2}{6} : 2\frac{2}{9} = \frac{32}{6} : \frac{20}{9} = \frac{32}{6} \cdot \frac{9}{20} = \frac{32 \cdot 9}{6 \cdot 20} = \frac{288}{120} = \frac{12}{5} = 2\frac{2}{5}$$

2. Вычислите:

a) $$2\frac{1}{2} \cdot 1\frac{1}{5} - 2\frac{2}{15} : 2 = \frac{5}{2} \cdot \frac{6}{5} - \frac{32}{15} : 2 = \frac{5 \cdot 6}{2 \cdot 5} - \frac{32}{15} \cdot \frac{1}{2} = \frac{30}{10} - \frac{32}{30} = 3 - \frac{16}{15} = \frac{45}{15} - \frac{16}{15} = \frac{45-16}{15} = \frac{29}{15} = 1\frac{14}{15}$$