Let A be the event that the toaster lasts more than a year. P(A) = 0.97.
Let B be the event that the toaster lasts more than two years. P(B) = 0.88.
We want to find the probability that the toaster lasts less than two years but more than a year. This is the probability of event A occurring but not event B.
P(A and not B) = P(A) - P(A and B). Since B is a subset of A (if it lasts more than two years, it must last more than one year), P(A and B) = P(B).
P(A and not B) = P(A) - P(B) = 0.97 - 0.88 = 0.09.