ВПР. Математика. 8 класс Базовый уровене Образец Найдите значение выраженна 8

\begin{aligned} &\frac{(x+1)^2}{8x} + \frac{4x}{x+y} \\ & \text{При } x = \sqrt{3}, y = 6.2 \\ &\frac{(\sqrt{3}+1)^2}{8\sqrt{3}} + \frac{4\sqrt{3}}{\sqrt{3}+6.2} = \frac{3+2\sqrt{3}+1}{8\sqrt{3}} + \frac{4\sqrt{3}}{\sqrt{3}+6.2} = \frac{4+2\sqrt{3}}{8\sqrt{3}} + \frac{4\sqrt{3}}{\sqrt{3}+6.2} = \\ &= \frac{2+\sqrt{3}}{4\sqrt{3}} + \frac{4\sqrt{3}}{\sqrt{3}+6.2} = \frac{(2+\sqrt{3})(\sqrt{3}+6.2) + 4\sqrt{3} \cdot 4\sqrt{3}}{4\sqrt{3}(\sqrt{3}+6.2)} = \frac{2\sqrt{3}+12.4+3+6.2\sqrt{3}+48}{4\sqrt{3}(\sqrt{3}+6.2)} = \\ & = \frac{63.4+8.2\sqrt{3}}{4\sqrt{3}(\sqrt{3}+6.2)} = \frac{63.4+8.2\sqrt{3}}{12 + 24.8\sqrt{3}} = \frac{(63.4+8.2\sqrt{3})(12 - 24.8\sqrt{3})}{(12 + 24.8\sqrt{3})(12 - 24.8\sqrt{3})} = \\ &= \frac{760.8 - 1572.32\sqrt{3} + 98.4\sqrt{3} - 339.408}{144 - 1537.5} = \frac{421.392 - 1473.92\sqrt{3}}{-1393.5} \approx 8 \end{aligned}