Выполним вычисления:
$$4\frac{3}{17} - 2\frac{1}{5} = \frac{4 \cdot 17 + 3}{17} - \frac{2 \cdot 5 + 1}{5} = \frac{71}{17} - \frac{11}{5} = \frac{71 \cdot 5 - 11 \cdot 17}{17 \cdot 5} = \frac{355 - 187}{85} = \frac{168}{85} = 1\frac{83}{85}$$
$$4\frac{1}{13} + 4\frac{8}{9} = \frac{4 \cdot 13 + 1}{13} + \frac{4 \cdot 9 + 8}{9} = \frac{53}{13} + \frac{44}{9} = \frac{53 \cdot 9 + 44 \cdot 13}{13 \cdot 9} = \frac{477 + 572}{117} = \frac{1049}{117} = 8\frac{113}{117}$$
$$13\frac{8}{9} - 1\frac{11}{18} = \frac{13 \cdot 9 + 8}{9} - \frac{1 \cdot 18 + 11}{18} = \frac{125}{9} - \frac{29}{18} = \frac{125 \cdot 2 - 29}{18} = \frac{250 - 29}{18} = \frac{221}{18} = 12\frac{5}{18}$$
$$47\frac{13}{28} - 25\frac{5}{7} = \frac{47 \cdot 28 + 13}{28} - \frac{25 \cdot 7 + 5}{7} = \frac{1329}{28} - \frac{180}{7} = \frac{1329 - 180 \cdot 4}{28} = \frac{1329 - 720}{28} = \frac{609}{28} = 21\frac{21}{28} = 21\frac{3}{4}$$
$$26\frac{12}{23} + 3\frac{15}{46} = \frac{26 \cdot 23 + 12}{23} + \frac{3 \cdot 46 + 15}{46} = \frac{610}{23} + \frac{153}{46} = \frac{610 \cdot 2 + 153}{46} = \frac{1220 + 153}{46} = \frac{1373}{46} = 29\frac{39}{46}$$
$$4\frac{3}{26} - 2\frac{12}{13} = \frac{4 \cdot 26 + 3}{26} - \frac{2 \cdot 13 + 12}{13} = \frac{107}{26} - \frac{38}{13} = \frac{107 - 38 \cdot 2}{26} = \frac{107 - 76}{26} = \frac{31}{26} = 1\frac{5}{26}$$
Ответ: