7. Вычислим: $$ 39 : (\frac{7}{1} + \frac{6}{49}) = 39 : (\frac{7 \cdot 49}{1 \cdot 49} + \frac{6}{49}) = 39 : (\frac{343}{49} + \frac{6}{49}) = 39 : \frac{349}{49} = 39 \cdot \frac{49}{349} = \frac{39 \cdot 49}{349} = \frac{1911}{349} = 5\frac{166}{349} $$
Ответ: 5$$\frac{166}{349}$$