Решение задания 197

1. $$7\frac{9}{16}+8\frac{7}{16} = (7+8) + (\frac{9}{16}+\frac{7}{16}) = 15 + \frac{16}{16} = 15 + 1 = 16$$
2. $$4\frac{9}{19}+5\frac{13}{19} = (4+5) + (\frac{9}{19}+\frac{13}{19}) = 9 + \frac{22}{19} = 9 + 1\frac{3}{19} = 10\frac{3}{19}$$
3. $$1-\frac{16}{25} = \frac{25}{25} - \frac{16}{25} = \frac{9}{25}$$
4. $$4-1\frac{7}{12} = 3\frac{12}{12} - 1\frac{7}{12} = (3-1) + (\frac{12}{12}-\frac{7}{12}) = 2 + \frac{5}{12} = 2\frac{5}{12}$$
5. $$6\frac{5}{14}-2\frac{11}{14} = 5\frac{19}{14}-2\frac{11}{14} = (5-2) + (\frac{19}{14}-\frac{11}{14}) = 3 + \frac{8}{14} = 3 + \frac{4}{7} = 3\frac{4}{7}$$
6. $$19\frac{11}{35}-12\frac{29}{35} = 18\frac{46}{35}-12\frac{29}{35} = (18-12) + (\frac{46}{35}-\frac{29}{35}) = 6 + \frac{17}{35} = 6\frac{17}{35}$$