3. Вычислите: 3\frac{3}{7}-(6-2\frac{2}{3}) : \frac{1}{2}+\frac{4}{7}= Запишите полностью решение и ответ.

3\frac{3}{7} = \frac{3 \cdot 7 + 3}{7} = \frac{24}{7}

2\frac{2}{3} = \frac{2 \cdot 3 + 2}{3} = \frac{8}{3}

6 - \frac{8}{3} = \frac{6 \cdot 3}{3} - \frac{8}{3} = \frac{18}{3} - \frac{8}{3} = \frac{10}{3}

\frac{10}{3} : \frac{1}{2} = \frac{10}{3} \cdot 2 = \frac{20}{3}

\frac{24}{7} - \frac{20}{3} = \frac{24 \cdot 3}{7 \cdot 3} - \frac{20 \cdot 7}{3 \cdot 7} = \frac{72}{21} - \frac{140}{21} = \frac{-68}{21}

-\frac{68}{21} + \frac{4}{7} = -\frac{68}{21} + \frac{4 \cdot 3}{7 \cdot 3} = -\frac{68}{21} + \frac{12}{21} = \frac{-56}{21} = -\frac{8}{3} = -2\frac{2}{3}