9. Вычислите: $$(\frac{3}{4} \cdot \sqrt{32})^2 + 20 \cdot \sqrt{7\frac{9}{16}} + 2(\sqrt{8})^2$$

$$ \begin{aligned} (\frac{3}{4} \cdot \sqrt{32})^2 + 20 \cdot \sqrt{7\frac{9}{16}} + 2(\sqrt{8})^2 &= (\frac{3}{4})^2 \cdot (\sqrt{32})^2 + 20 \cdot \sqrt{\frac{7 \cdot 16 + 9}{16}} + 2 \cdot 8 = \frac{9}{16} \cdot 32 + 20 \cdot \sqrt{\frac{112+9}{16}} + 16 = \frac{9}{1} \cdot 2 + 20 \cdot \sqrt{\frac{121}{16}} + 16 = 18 + 20 \cdot \frac{11}{4} + 16 = 18 + 5 \cdot 11 + 16 = 18 + 55 + 16 = 89 \end{aligned} $$ Ответ: $$\boxed{89}$$