$$\frac{4}{3} + (-8\frac{1}{9} + 3\frac{8}{5}) : \frac{7}{6}$$
1) -8$$\frac{1}{9}$$ + 3$$\frac{8}{5}$$ = -$$\frac{73}{9}$$ + $$\frac{23}{5}$$ = -$$\frac{73 \cdot 5}{9 \cdot 5}$$ + $$\frac{23 \cdot 9}{5 \cdot 9}$$ = -$$\frac{365}{45}$$ + $$\frac{207}{45}$$ = -$$\frac{158}{45}$$
2) -$$\frac{158}{45}$$ : $$\frac{7}{6}$$ = -$$\frac{158}{45}$$ × $$\frac{6}{7}$$ = -$$\frac{158 \cdot 6}{45 \cdot 7}$$ = -$$\frac{158 \cdot 2}{15 \cdot 7}$$ = -$$\frac{316}{105}$$
3) $$\frac{4}{3}$$ - $$\frac{316}{105}$$ = $$\frac{4 \cdot 35}{3 \cdot 35}$$ - $$\frac{316}{105}$$ = $$\frac{140}{105}$$ - $$\frac{316}{105}$$ = -$$\frac{176}{105}$$ = -1$$\frac{71}{105}$$
Ответ: -1$$\frac{71}{105}$$