Решение:

1) $$\frac{11}{16} + \frac{3}{32} = \frac{11 \cdot 2}{16 \cdot 2} + \frac{3}{32} = \frac{22}{32} + \frac{3}{32} = \frac{22+3}{32} = \frac{25}{32}$$

2) $$\frac{55}{48} : \frac{25}{32} = \frac{55}{48} \cdot \frac{32}{25} = \frac{55 \cdot 32}{48 \cdot 25} = \frac{11 \cdot 5 \cdot 2 \cdot 16}{3 \cdot 16 \cdot 5 \cdot 5} = \frac{11 \cdot 2}{3 \cdot 5} = \frac{22}{15}$$

3) $$\frac{14}{15} \cdot \frac{5}{7} = \frac{14 \cdot 5}{15 \cdot 7} = \frac{2 \cdot 7 \cdot 5}{3 \cdot 5 \cdot 7} = \frac{2}{3}$$

4) $$\frac{22}{15} - \frac{2}{3} = \frac{22}{15} - \frac{2 \cdot 5}{3 \cdot 5} = \frac{22}{15} - \frac{10}{15} = \frac{22 - 10}{15} = \frac{12}{15} = \frac{4 \cdot 3}{5 \cdot 3} = \frac{4}{5}$$

Ответ: $$\frac{4}{5}$$