Ответ:
Приводим дроби к общему знаменателю, выполняем действия и сокращаем результат, когда это возможно.
- \(\frac{3}{8}+\frac{1}{6}=\frac{9}{24}+\frac{4}{24}=\frac{13}{24}\).
- \(\frac{5}{9}-\frac{1}{3}=\frac{5}{9}-\frac{3}{9}=\frac{2}{9}\).
- \(\frac{2}{5}+\frac{3}{10}=\frac{4}{10}+\frac{3}{10}=\frac{7}{10}\).
- \(\frac{7}{12}-\frac{1}{8}=\frac{14}{24}-\frac{3}{24}=\frac{11}{24}\).
- \(\frac{4}{7}+\frac{1}{3}=\frac{12}{21}+\frac{7}{21}=\frac{19}{21}\).
- \(\frac{5}{6}-\frac{2}{5}=\frac{25}{30}-\frac{12}{30}=\frac{13}{30}\).
- \(\frac{1}{4}+\frac{2}{9}-\frac{1}{6}=\frac{9}{36}+\frac{8}{36}-\frac{6}{36}=\frac{11}{36}\).
- \(\frac{3}{5}-\frac{1}{10}+\frac{1}{2}=\frac{6}{10}-\frac{1}{10}+\frac{5}{10}=1\).
- \(\frac{7}{8}-\frac{1}{4}+\frac{1}{3}=\frac{21}{24}-\frac{6}{24}+\frac{8}{24}=\frac{23}{24}\).
- \(\frac{2}{3}+\frac{1}{5}-\frac{1}{15}=\frac{10}{15}+\frac{3}{15}-\frac{1}{15}=\frac{12}{15}=\frac{4}{5}\).
