5. Вычислите значение дробного выражения: 1) \(\frac{(\frac{3}{2}+1,75) \cdot 0,6}{6\frac{7}{12}-2,25}\); 2) \(\frac{4,4:1\frac{3}{5}+2\frac{4}{7}-8\frac{1}{2}:14}{2\frac{3}{8}-1\frac{11}{14}}\\)

1) \(\frac{(\frac{3}{2}+1,75) \cdot 0,6}{6\frac{7}{12}-2,25}=\frac{(1,5+1,75) \cdot 0,6}{6\frac{7}{12}-2,25}=\frac{3,25 \cdot 0,6}{6\frac{7}{12}-2,25}=\frac{1,95}{6\frac{7}{12}-2,25}=\frac{1,95}{6,58(3)-2,25}=\frac{1,95}{4,33(3)}=\frac{195}{433,3(3)} \approx 0,45\)

2) \(\frac{4,4:1\frac{3}{5}+2\frac{4}{7}-8\frac{1}{2}:14}{2\frac{3}{8}-1\frac{11}{14}}=\frac{4,4:\frac{8}{5}+\frac{18}{7}-\frac{17}{2}:14}{\frac{19}{8}-\frac{25}{14}}=\frac{\frac{44}{10} \cdot \frac{5}{8}+\frac{18}{7}-\frac{17}{2} \cdot \frac{1}{14}}{\frac{19}{8}-\frac{25}{14}}=\frac{\frac{11}{1} \cdot \frac{1}{4}+\frac{18}{7}-\frac{17}{28}}{\frac{19}{8}-\frac{25}{14}}=\frac{\frac{11}{4}+\frac{18}{7}-\frac{17}{28}}{\frac{19 \cdot 7 - 25 \cdot 4}{56}}=\frac{\frac{11 \cdot 7 + 18 \cdot 4 - 17}{28}}{\frac{133-100}{56}}=\frac{\frac{77 + 72 - 17}{28}}{\frac{33}{56}}=\frac{\frac{132}{28}}{\frac{33}{56}}=\frac{132}{28} \cdot \frac{56}{33}=\frac{4}{1} \cdot \frac{2}{1}=8\)

Ответ: 1) \(\approx 0,45\); 2) \(8\)