Вопрос:

Вычислите значения выражений в столбце А.

Ответ:

Решения для столбца А: 1. $$\frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$$ 2. $$1\frac{1}{2} + \frac{1}{3} = \frac{3}{2} + \frac{1}{3} = \frac{9}{6} + \frac{2}{6} = \frac{11}{6} = 1\frac{5}{6}$$ 3. $$\frac{3}{5} + \frac{1}{10} = \frac{6}{10} + \frac{1}{10} = \frac{7}{10}$$ 4. $$1\frac{1}{12} + \frac{5}{6} = \frac{13}{12} + \frac{10}{12} = \frac{23}{12} = 1\frac{11}{12}$$ 5. $$\frac{1}{3} + 1\frac{1}{4} = \frac{1}{3} + \frac{5}{4} = \frac{4}{12} + \frac{15}{12} = \frac{19}{12} = 1\frac{7}{12}$$ 6. $$\frac{1}{3} + \frac{1}{5} = \frac{5}{15} + \frac{3}{15} = \frac{8}{15}$$ 7. $$1\frac{1}{2} - \frac{2}{4} = \frac{3}{2} - \frac{1}{2} = \frac{2}{2} = 1$$ 8. $$\frac{8}{7} - 1 = \frac{8}{7} - \frac{7}{7} = \frac{1}{7}$$ 9. $$1\frac{1}{4} + \frac{1}{5} = \frac{5}{4} + \frac{1}{5} = \frac{25}{20} + \frac{4}{20} = \frac{29}{20} = 1\frac{9}{20}$$ 10. $$\frac{1}{2} + \frac{3}{7} = \frac{7}{14} + \frac{6}{14} = \frac{13}{14}$$ 11. $$\frac{3}{4} - \frac{1}{8} = \frac{6}{8} - \frac{1}{8} = \frac{5}{8}$$ 12. $$1\frac{1}{6} + \frac{5}{6} = \frac{7}{6} + \frac{5}{6} = \frac{12}{6} = 2$$ 13. $$4\frac{2}{15} + \frac{5}{5} = \frac{62}{15} + 1 = \frac{62}{15} + \frac{15}{15} = \frac{77}{15} = 5\frac{2}{15}$$ 14. $$\frac{7}{10} - \frac{1}{2} = \frac{7}{10} - \frac{5}{10} = \frac{2}{10} = \frac{1}{5}$$ 15. $$\frac{1}{3} - \frac{1}{4} = \frac{4}{12} - \frac{3}{12} = \frac{1}{12}$$
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