Решения для столбца А:
1. $$\frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2}$$
2. $$1\frac{1}{2} + \frac{1}{3} = \frac{3}{2} + \frac{1}{3} = \frac{9}{6} + \frac{2}{6} = \frac{11}{6} = 1\frac{5}{6}$$
3. $$\frac{3}{5} + \frac{1}{10} = \frac{6}{10} + \frac{1}{10} = \frac{7}{10}$$
4. $$1\frac{1}{12} + \frac{5}{6} = \frac{13}{12} + \frac{10}{12} = \frac{23}{12} = 1\frac{11}{12}$$
5. $$\frac{1}{3} + 1\frac{1}{4} = \frac{1}{3} + \frac{5}{4} = \frac{4}{12} + \frac{15}{12} = \frac{19}{12} = 1\frac{7}{12}$$
6. $$\frac{1}{3} + \frac{1}{5} = \frac{5}{15} + \frac{3}{15} = \frac{8}{15}$$
7. $$1\frac{1}{2} - \frac{2}{4} = \frac{3}{2} - \frac{1}{2} = \frac{2}{2} = 1$$
8. $$\frac{8}{7} - 1 = \frac{8}{7} - \frac{7}{7} = \frac{1}{7}$$
9. $$1\frac{1}{4} + \frac{1}{5} = \frac{5}{4} + \frac{1}{5} = \frac{25}{20} + \frac{4}{20} = \frac{29}{20} = 1\frac{9}{20}$$
10. $$\frac{1}{2} + \frac{3}{7} = \frac{7}{14} + \frac{6}{14} = \frac{13}{14}$$
11. $$\frac{3}{4} - \frac{1}{8} = \frac{6}{8} - \frac{1}{8} = \frac{5}{8}$$
12. $$1\frac{1}{6} + \frac{5}{6} = \frac{7}{6} + \frac{5}{6} = \frac{12}{6} = 2$$
13. $$4\frac{2}{15} + \frac{5}{5} = \frac{62}{15} + 1 = \frac{62}{15} + \frac{15}{15} = \frac{77}{15} = 5\frac{2}{15}$$
14. $$\frac{7}{10} - \frac{1}{2} = \frac{7}{10} - \frac{5}{10} = \frac{2}{10} = \frac{1}{5}$$
15. $$\frac{1}{3} - \frac{1}{4} = \frac{4}{12} - \frac{3}{12} = \frac{1}{12}$$