Решение:
a) $$6\frac{1}{3} - 8 = \frac{19}{3} - \frac{24}{3} = -\frac{5}{3} = -1\frac{2}{3}$$
б) $$-2\frac{2}{7} + 4\frac{3}{5} = -\frac{16}{7} + \frac{23}{5} = \frac{-16 \cdot 5 + 23 \cdot 7}{35} = \frac{-80 + 161}{35} = \frac{81}{35} = 2\frac{11}{35}$$
в) $$5\frac{1}{3} - 6\frac{1}{4} = \frac{16}{3} - \frac{25}{4} = \frac{16 \cdot 4 - 25 \cdot 3}{12} = \frac{64 - 75}{12} = -\frac{11}{12}$$
г) $$\frac{3}{8} : (-\frac{9}{16}) = \frac{3}{8} \cdot (-\frac{16}{9}) = -\frac{3 \cdot 16}{8 \cdot 9} = -\frac{3 \cdot 2}{1 \cdot 9} = -\frac{6}{9} = -\frac{2}{3}$$
д) $$\frac{5}{12} \cdot (-6) = -\frac{5 \cdot 6}{12} = -\frac{5 \cdot 1}{2} = -\frac{5}{2} = -2\frac{1}{2}$$
е) $$-3\frac{2}{9} \cdot 3 = -\frac{29}{9} \cdot 3 = -\frac{29 \cdot 3}{9} = -\frac{29}{3} = -9\frac{2}{3}$$
ж) $$\frac{4}{7} \cdot (-49) = -\frac{4 \cdot 49}{7} = -4 \cdot 7 = -28$$
з) $$-16 : (-\frac{4}{9}) = -16 \cdot (-\frac{9}{4}) = \frac{16 \cdot 9}{4} = 4 \cdot 9 = 36$$
Ответ:
a) $$-1\frac{2}{3}$$
б) $$2\frac{11}{35}$$
в) $$- \frac{11}{12}$$
г) $$- \frac{2}{3}$$
д) $$-2\frac{1}{2}$$
е) $$-9\frac{2}{3}$$
ж) $$-28$$
з) $$36$$