445 Вычислите: a) \(\frac{1}{2} + \frac{1}{3}\) b) \(\frac{1}{3} + \frac{2}{7}\) v) \(\frac{2}{5} + \frac{1}{3}\) g) \(\frac{3}{7} + \frac{4}{9}\) d) \(\frac{5}{9} - \frac{1}{6}\) e) \(\frac{3}{4} - \(\frac{1}{3}\) z) \(\frac{1}{6} + \frac{1}{8}\) i) \(\frac{9}{5} - \frac{7}{10}\) i) \(\frac{1}{2} - \frac{3}{8}\) k) \(\frac{7}{15} - \frac{3}{10}\) l) \(\frac{3}{8} + \frac{5}{12}\) m) \(\frac{5}{9} - \frac{1}{6}\) n) \(\frac{5}{11} + \frac{3}{5}\) o) \(\frac{17}{30} - \frac{3}{6}\) p) \(\frac{17}{35} - \frac{4}{15}\)

Решение: a) \(\frac{1}{2} + \frac{1}{3} = \frac{3}{6} + \frac{2}{6} = \frac{5}{6}\) b) \(\frac{1}{3} + \frac{2}{7} = \frac{7}{21} + \frac{6}{21} = \frac{13}{21}\) v) \(\frac{2}{5} + \frac{1}{3} = \frac{6}{15} + \frac{5}{15} = \frac{11}{15}\) g) \(\frac{3}{7} + \frac{4}{9} = \frac{27}{63} + \frac{28}{63} = \frac{55}{63}\) d) \(\frac{5}{9} - \frac{1}{6} = \frac{10}{18} - \frac{3}{18} = \frac{7}{18}\) e) \(\frac{3}{4} - \frac{1}{3} = \frac{9}{12} - \frac{4}{12} = \frac{5}{12}\) z) \(\frac{1}{6} + \frac{1}{8} = \frac{4}{24} + \frac{3}{24} = \frac{7}{24}\) i) \(\frac{9}{5} - \frac{7}{10} = \frac{18}{10} - \frac{7}{10} = \frac{11}{10} = 1\frac{1}{10}\) i) \(\frac{1}{2} - \frac{3}{8} = \frac{4}{8} - \frac{3}{8} = \frac{1}{8}\) k) \(\frac{7}{15} - \frac{3}{10} = \frac{14}{30} - \frac{9}{30} = \frac{5}{30} = \frac{1}{6}\) l) \(\frac{3}{8} + \frac{5}{12} = \frac{9}{24} + \frac{10}{24} = \frac{19}{24}\) m) \(\frac{5}{9} - \frac{1}{6} = \frac{10}{18} - \frac{3}{18} = \frac{7}{18}\) n) \(\frac{5}{11} + \frac{3}{5} = \frac{25}{55} + \frac{33}{55} = \frac{58}{55} = 1 \frac{3}{55}\) o) \(\frac{17}{30} - \frac{3}{6} = \frac{17}{30} - \frac{15}{30} = \frac{2}{30} = \frac{1}{15}\) p) \(\frac{17}{35} - \frac{4}{15} = \frac{51}{105} - \frac{28}{105} = \frac{23}{105}\)