Решение:

д) $$7 \frac{2}{9} + 4 = 7 + \frac{2}{9} + 4 = 11 \frac{2}{9}$$

ж) $$7 + 3 \frac{5}{8} = 7 + 3 + \frac{5}{8} = 10 \frac{5}{8}$$

e) $$8 \frac{3}{5} + \frac{1}{15} = 8 + \frac{3}{5} + \frac{1}{15} = 8 + \frac{3 \cdot 3}{5 \cdot 3} + \frac{1}{15} = 8 + \frac{9}{15} + \frac{1}{15} = 8 + \frac{10}{15} = 8 \frac{2}{3}$$

з) $$\frac{2}{3} + 4 \frac{3}{5} = \frac{2}{3} + 4 + \frac{3}{5} = 4 + \frac{2}{3} + \frac{3}{5} = 4 + \frac{2 \cdot 5}{3 \cdot 5} + \frac{3 \cdot 3}{5 \cdot 3} = 4 + \frac{10}{15} + \frac{9}{15} = 4 + \frac{19}{15} = 4 + 1 \frac{4}{15} = 5 \frac{4}{15}$$

Ответ:

• д) $$11 \frac{2}{9}$$
• ж) $$10 \frac{5}{8}$$
• e) $$8 \frac{2}{3}$$
• з) $$5 \frac{4}{15}$$