2. Выполни действия: \((\frac{2}{3} + \frac{9}{10}) + (\frac{1}{3})^2 - \frac{2}{5} : \frac{7}{9}\)

1) \(\frac{2}{3} + \frac{9}{10} = \frac{2 \cdot 10 + 9 \cdot 3}{30} = \frac{20 + 27}{30} = \frac{47}{30}\) 2) \((\frac{1}{3})^2 = \frac{1}{3} \cdot \frac{1}{3} = \frac{1}{9}\) 3) \(\frac{2}{5} : \frac{7}{9} = \frac{2}{5} \cdot \frac{9}{7} = \frac{18}{35}\) 4) \(\frac{47}{30} + \frac{1}{9} = \frac{47 \cdot 3 + 1 \cdot 10}{90} = \frac{141 + 10}{90} = \frac{151}{90}\) 5) \(\frac{151}{90} - \frac{18}{35} = \frac{151 \cdot 7 - 18 \cdot 18}{630} = \frac{1057 - 324}{630} = \frac{733}{630} = 1\frac{103}{630}\) Ответ: \(1\frac{103}{630}\)