Ответ:
Приведём дроби к общему знаменателю: \(4\frac{3}{4}+2\frac{3}{8}=4\frac{6}{8}+2\frac{3}{8}=6\frac{9}{8}=7\frac{1}{8}\).
\(3\frac{2}{3}+3\frac{3}{4}=6+\frac{8}{12}+\frac{9}{12}=6\frac{17}{12}=7\frac{5}{12}\).
\(5\frac{7}{15}+1\frac{3}{20}=6+\frac{28}{60}+\frac{9}{60}=6\frac{37}{60}\).
\(\frac{7}{9}+1\frac{7}{9}=1+\frac{14}{9}=2\frac{5}{9}\).
\(\frac{3}{16}+\frac{1}{16}=\frac{4}{16}=\frac{1}{4}\).
\(5\frac{2}{3}+5\frac{2}{3}=10+\frac{4}{3}=11\frac{1}{3}\).
\(\frac{8}{9}+3=3\frac{8}{9}\).
\(3\frac{8}{15}+3\frac{7}{15}=6+\frac{15}{15}=7\).
