Ответ:
\(2\frac{1}{6}-1\frac{1}{16}=1+\frac{8}{48}-\frac{3}{48}=1\frac{5}{48}\).
\(4\frac{9}{13}-1\frac{9}{13}=3\).
\(2\frac{9}{17}-\frac{2}{3}=2+\frac{27}{51}-\frac{34}{51}=1\frac{44}{51}\).
\(1\frac{5}{21}-\frac{4}{7}=1+\frac{5}{21}-\frac{12}{21}=\frac{14}{21}=\frac{2}{3}\).
Займём единицу: \(5\frac{8}{11}=4\frac{19}{11}\). Тогда \(4\frac{19}{11}-3\frac{10}{11}=1\frac{9}{11}\).
\(5-2\frac{5}{6}=4\frac{6}{6}-2\frac{5}{6}=2\frac{1}{6}\).
\(2\frac{4}{9}-2=\frac{4}{9}\).
\(5\frac{17}{18}-\frac{11}{18}=5\frac{6}{18}=5\frac{1}{3}\).
