Выполним действия с дробями:
- A) $$\frac{5}{8} + \frac{3}{7} = \frac{5 \cdot 7}{8 \cdot 7} + \frac{3 \cdot 8}{7 \cdot 8} = \frac{35}{56} + \frac{24}{56} = \frac{35+24}{56} = \frac{59}{56} = 1\frac{3}{56}$$
- Б) $$1\frac{1}{5} + 2\frac{3}{10} = 1 + \frac{1}{5} + 2 + \frac{3}{10} = 3 + \frac{1}{5} + \frac{3}{10} = 3 + \frac{1 \cdot 2}{5 \cdot 2} + \frac{3}{10} = 3 + \frac{2}{10} + \frac{3}{10} = 3 + \frac{2+3}{10} = 3 + \frac{5}{10} = 3 + \frac{1}{2} = 3\frac{1}{2}$$
- В) $$\frac{17}{20} - \frac{3}{4} = \frac{17}{20} - \frac{3 \cdot 5}{4 \cdot 5} = \frac{17}{20} - \frac{15}{20} = \frac{17-15}{20} = \frac{2}{20} = \frac{1}{10}$$
- Г) $$\frac{5}{6} - \frac{2}{9} = \frac{5 \cdot 3}{6 \cdot 3} - \frac{2 \cdot 2}{9 \cdot 2} = \frac{15}{18} - \frac{4}{18} = \frac{15-4}{18} = \frac{11}{18}$$
Ответ: A) $$1\frac{3}{56}$$; Б) $$3\frac{1}{2}$$; В) $$\frac{1}{10}$$; Г) $$\frac{11}{18}$$