8. Выполните деление, рассуждая, как в предыдущем примере: 8 a) 16:8= 9 6 6) 120: 3 = 7 4 34:2= 9 5 35:5= 8 16 в) 64:4= 21 6 38-12- 11 50 100:25 = 109

• a) $$16\frac{8}{9} : 8 = (16 + \frac{8}{9}) : 8 = 16:8 + \frac{8}{9}:8 = 2 + \frac{8}{9} \cdot \frac{1}{8} = 2 + \frac{1}{9} = 2\frac{1}{9}$$


• б) $$120\frac{6}{7} : 3 = (120 + \frac{6}{7}) : 3 = 120:3 + \frac{6}{7}:3 = 40 + \frac{6}{7} \cdot \frac{1}{3} = 40 + \frac{2}{7} = 40\frac{2}{7}$$


• в) $$34\frac{4}{9} : 2 = (34 + \frac{4}{9}) : 2 = 34:2 + \frac{4}{9}:2 = 17 + \frac{4}{9} \cdot \frac{1}{2} = 17 + \frac{2}{9} = 17\frac{2}{9}$$


• г) $$35\frac{5}{8} : 5 = (35 + \frac{5}{8}) : 5 = 35:5 + \frac{5}{8}:5 = 7 + \frac{5}{8} \cdot \frac{1}{5} = 7 + \frac{1}{8} = 7\frac{1}{8}$$


• д) $$64\frac{16}{21} : 4 = (64 + \frac{16}{21}) : 4 = 64:4 + \frac{16}{21}:4 = 16 + \frac{16}{21} \cdot \frac{1}{4} = 16 + \frac{4}{21} = 16\frac{4}{21}$$


• e) $$38\frac{6}{11} : 2 = (38 + \frac{6}{11}) : 2 = 38:2 + \frac{6}{11}:2 = 19 + \frac{6}{11} \cdot \frac{1}{2} = 19 + \frac{3}{11} = 19\frac{3}{11}$$


• ж) $$100\frac{50}{109} : 25 = (100 + \frac{50}{109}) : 25 = 100:25 + \frac{50}{109}:25 = 4 + \frac{50}{109} \cdot \frac{1}{25} = 4 + \frac{2}{109} = 4\frac{2}{109}$$

Ответ: a) $$2\frac{1}{9}$$, б) $$40\frac{2}{7}$$, в) $$17\frac{2}{9}$$, г) $$7\frac{1}{8}$$, д) $$16\frac{4}{21}$$, e) $$19\frac{3}{11}$$, ж) $$4\frac{2}{109}$$