- a) \(\frac{14}{18} - \frac{5}{18} = \frac{14-5}{18} = \frac{9}{18} = \frac{1}{2}\)
- б) \(\frac{5}{22} + \frac{6}{22} = \frac{5+6}{22} = \frac{11}{22} = \frac{1}{2}\)
- в) \(6 \frac{7}{12} - 1 \frac{3}{12} = (6-1) + \frac{7-3}{12} = 5 + \frac{4}{12} = 5 + \frac{1}{3} = 5 \frac{1}{3}\)
- г) \(7 \frac{5}{27} + 3 \frac{4}{27} = (7+3) + \frac{5+4}{27} = 10 + \frac{9}{27} = 10 + \frac{1}{3} = 10 \frac{1}{3}\)
Ответ: a) \(\frac{1}{2}\); б) \(\frac{1}{2}\); в) \(5 \frac{1}{3}\); г) \(10 \frac{1}{3}\)