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a) \(\frac{14}{18} - \frac{5}{18} = \frac{14-5}{18} = \frac{9}{18} = \frac{1}{2}\)
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б) \(\frac{5}{6} + \frac{5}{6} = \frac{5+5}{6} = \frac{10}{6} = \frac{5}{3} = 1\frac{2}{3}\)
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в) \(6 - \frac{7}{12} = \frac{6 \cdot 12}{12} - \frac{7}{12} = \frac{72-7}{12} = \frac{65}{12} = 5\frac{5}{12}\)
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г) \(7 \frac{5}{27} + 3\frac{4}{27} = (7+3) + (\frac{5}{27} + \frac{4}{27}) = 10 + \frac{5+4}{27} = 10 + \frac{9}{27} = 10 + \frac{1}{3} = 10\frac{1}{3}\)
Ответ: a) \(\frac{1}{2}\); б) \(1\frac{2}{3}\); в) \(5\frac{5}{12}\); г) \(10\frac{1}{3}\)