Решение задания 4

a) $$\frac{5}{6} + \frac{4}{1} = \frac{5}{6} + \frac{24}{6} = \frac{5+24}{6} = \frac{29}{6} = 4\frac{5}{6}$$

б) $$\frac{10}{3} - \frac{15}{4} = \frac{40}{12} - \frac{45}{12} = \frac{40-45}{12} = \frac{-5}{12} = -\frac{5}{12}$$

г) $$ 5 - 3\frac{2}{7} = 5 - \frac{23}{7} = \frac{35}{7} - \frac{23}{7} = \frac{35-23}{7} = \frac{12}{7} = 1\frac{5}{7}$$

д) $$ \frac{4}{3} : \frac{9}{8} = \frac{4}{3} \cdot \frac{8}{9} = \frac{4 \cdot 8}{3 \cdot 9} = \frac{32}{27} = 1\frac{5}{27}$$

е) $$ \frac{10}{9} : \frac{8}{5} = \frac{10}{9} \cdot \frac{5}{8} = \frac{10 \cdot 5}{9 \cdot 8} = \frac{50}{72} = \frac{25}{36}$$

ж) $$ 2\frac{6}{8} : 1\frac{1}{7} = \frac{22}{8} : \frac{8}{7} = \frac{22}{8} \cdot \frac{7}{8} = \frac{22 \cdot 7}{8 \cdot 8} = \frac{154}{64} = \frac{77}{32} = 2\frac{13}{32}$$

з) $$ 6\frac{3}{5} \cdot 10 = \frac{33}{5} \cdot 10 = \frac{33 \cdot 10}{5} = \frac{330}{5} = 66$$