a) $$ \frac{2}{3} + \frac{7}{12} = \frac{2 \cdot 4}{3 \cdot 4} + \frac{7}{12} = \frac{8}{12} + \frac{7}{12} = \frac{8+7}{12} = \frac{15}{12} = \frac{5}{4} = 1\frac{1}{4} $$
б) $$ \frac{3}{4} + \frac{3}{8} = \frac{3 \cdot 2}{4 \cdot 2} + \frac{3}{8} = \frac{6}{8} + \frac{3}{8} = \frac{6+3}{8} = \frac{9}{8} = 1\frac{1}{8} $$
в) $$ \frac{3}{8} + \frac{13}{24} = \frac{3 \cdot 3}{8 \cdot 3} + \frac{13}{24} = \frac{9}{24} + \frac{13}{24} = \frac{9+13}{24} = \frac{22}{24} = \frac{11}{12} $$
Ответ: а) $$1\frac{1}{4}$$, б) $$1\frac{1}{8}$$, в) $$\frac{11}{12}$$