17. Выполните действия с радикалами $$(\frac{1}{2}\sqrt{6}-3\sqrt{3}+5\sqrt{2}-\sqrt{8}) \sqrt{24}+18\sqrt{2}-12\sqrt{3}$$.

$$\left(\frac{1}{2}\sqrt{6}-3\sqrt{3}+5\sqrt{2}-\sqrt{8}\right) \sqrt{24}+18\sqrt{2}-12\sqrt{3} = $$ $$\left(\frac{1}{2}\sqrt{6}-3\sqrt{3}+5\sqrt{2}-2\sqrt{2}\right) (2\sqrt{6})+18\sqrt{2}-12\sqrt{3} = $$ $$\left(\frac{1}{2}\sqrt{6}-3\sqrt{3}+3\sqrt{2}\right) (2\sqrt{6})+18\sqrt{2}-12\sqrt{3} = $$ $$\sqrt{6} * \sqrt{6} - 6\sqrt{18} + 6\sqrt{12} + 18\sqrt{2} - 12\sqrt{3} = $$ $$6 - 6 * 3\sqrt{2} + 6 * 2\sqrt{3} + 18\sqrt{2} - 12\sqrt{3} = $$ $$6 - 18\sqrt{2} + 12\sqrt{3} + 18\sqrt{2} - 12\sqrt{3} = 6$$ Ответ: 6