Вариант В1:
a) \( \left( 7 \frac{9}{17} + 4 \frac{4}{13} \right) - \left( 6 \frac{9}{17} + 3 \frac{9}{13} \right) \)
\( 7 \frac{9}{17} = \frac{7 \cdot 17 + 9}{17} = \frac{119 + 9}{17} = \frac{128}{17} \)
\( 4 \frac{4}{13} = \frac{4 \cdot 13 + 4}{13} = \frac{52 + 4}{13} = \frac{56}{13} \)
\( 6 \frac{9}{17} = \frac{6 \cdot 17 + 9}{17} = \frac{102 + 9}{17} = \frac{111}{17} \)
\( 3 \frac{9}{13} = \frac{3 \cdot 13 + 9}{13} = \frac{39 + 9}{13} = \frac{48}{13} \)
\( \left( \frac{128}{17} + \frac{56}{13} \right) - \left( \frac{111}{17} + \frac{48}{13} \right) \)
\( \frac{128}{17} + \frac{56}{13} - \frac{111}{17} - \frac{48}{13} \)
\( \left( \frac{128}{17} - \frac{111}{17} \right) + \left( \frac{56}{13} - \frac{48}{13} \right) \)
\( \frac{128 - 111}{17} + \frac{56 - 48}{13} = \frac{17}{17} + \frac{8}{13} = 1 + \frac{8}{13} \)
\( 1 \frac{8}{13} \)
Вариант В2:
a) \( \left( 9 \frac{5}{18} + 7 \frac{6}{17} \right) - \left( 8 \frac{5}{18} + 6 \frac{11}{17} \right) \)
\( 9 \frac{5}{18} = \frac{9 \cdot 18 + 5}{18} = \frac{162 + 5}{18} = \frac{167}{18} \)
\( 7 \frac{6}{17} = \frac{7 \cdot 17 + 6}{17} = \frac{119 + 6}{17} = \frac{125}{17} \)
\( 8 \frac{5}{18} = \frac{8 \cdot 18 + 5}{18} = \frac{144 + 5}{18} = \frac{149}{18} \)
\( 6 \frac{11}{17} = \frac{6 \cdot 17 + 11}{17} = \frac{102 + 11}{17} = \frac{113}{17} \)
\( \left( \frac{167}{18} + \frac{125}{17} \right) - \left( \frac{149}{18} + \frac{113}{17} \right) \)
\( \frac{167}{18} + \frac{125}{17} - \frac{149}{18} - \frac{113}{17} \)
\( \left( \frac{167}{18} - \frac{149}{18} \right) + \left( \frac{125}{17} - \frac{113}{17} \right) \)
\( \frac{167 - 149}{18} + \frac{125 - 113}{17} = \frac{18}{18} + \frac{12}{17} = 1 + \frac{12}{17} \)
\( 1 \frac{12}{17} \)
Ответ: Вариант В1: \( 1 \frac{8}{13} \). Вариант В2: \( 1 \frac{12}{17} \).